python - Open a webpage and return a dictionary of links on that page -

i wanted write function opens webpage , returns dictionary of links , text on page. tried it's giving me error. can do?

def process(url):     myopener = myopener()     #page = urllib.urlopen(url)     page = myopener.open(url)      text = page.read()     page.close() 

example input

<a href='http://my.computer .com/some/file.html'>link text</a> 

output

{"http://my.computer.com/some/file.html":link text.."} 

welcome stack overflow,

you haven't shown myopener does, have used own. code uses python 3 , beautiful soup 4 html parser (a personal favorite) on python wikipedia article.

root_url = "https://en.wikipedia.org" html_string = retrieve_webage(root_url + "/wiki/python_%28programming_language%29") soup = beautifulsoup(html_string) output = {} # can redefine soup here parse part of page link in soup.find_all('a'):     linkhref = link.get('href')     if not linkhref:         # ingnore blank hyperlinks         pass     elif linkhref[0] == '/':         # add root url relitive links         linkhref = root_url + linkhref     output[linkhref] = link.text 

this script overwrite links identical href attributes reads them down page. can learn more beautiful soup here.

feel free comment below if have questions