Java recurrence relation with for loop -

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public int algo(int n) {     if (n == 1) {         return 1;     }     algo(n/2);     (int = 0; < 4; i++) {         system.out.print(i);     }     return 0; }

i know recursive call mean t(n/2) how loop affect recurrence relation?

edit: attempt.

i think loop run log n times because run every time algo(int n) run. , algo run log n times because n keeps on being divided 2. also, loop runs 4 iterations. think add 4 log n recurrence o(n) = t(n/2) + 4 log n.

since loop constant time , , not vary n . should not affect time complexity.


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