r - ddply colSums and count of column together -

-

i'm new r , have pieced syntax below based on other helpful suggestions here on stackoverflow. i'm trying sum column called "combined hours" , count of column called doc_line_num grouped column doc_num.

so each doc_num, calculate sum combined_hours, , show count of doc_line_num.

the syntax below works fine column sum of combined_hours how incorporate count logic syntax doc_line_num?

thank you.

train2 <- ddply(train, c("weeknum", "doc_num", "doc_line_num", "short_date","cust_code", "op_code", "job_tp_code"), function(x) colsums(x[c("combined_hours")]))  # sample data  weeknum doc_num doc_line_num short_date cust_code  op_code job_tp_code combined_hours 40  227555            1 2015-10-02    dotsug ndona          pu      0.0269448 40  227555            3 2015-10-02    dotsug ndona          pu      0.4183320

using old-school plyr, should able 

ddply(train, .variables = "doc_num", summarize,       n_doc_line_num = length(unique(doc_line_num)),       sum_comb_hours = sum(combined_hours))

the ddply function has been replaced new dplyr package. using dplyr, written:

library(dplyr) train %>% group_by(doc_num) %>%     summarize(n_doc_line_num = n_distinct(doc_line_num),               sum_comb_hours = sum(combined_hours))

i assumed "a count of column called doc_line_num" mean count of distinct values.

if share larger bit of sample data (preferably dput, dput(droplevels(head(train, 10))) i'd happy test make sure things good.

both in dplyr , in plyr::ddply, summarize drop column aren't grouping variables. if want rest of columns retained (and have same value each value of doc_num) can add them grouping retain them. (by "the grouping" mean dplyr::group_by or .variables argument of plyr::ddply.)


Comments

Post a Comment

Popular posts from this blog

java - Static nested class instance -

-
this question has answer here: java inner class , static nested class 23 answers i came across in java, know static nested class why create instance of 'static'. isn't whole idea of 'static' use without instance? understand concept of inner classes, why (and frankly how possible to) create 'instance' of 'static' member @ ? why this: 1- outerclass.staticnestedclass nestedobject = new outerclass.staticnestedclass(); 2- nestedobject.anestedclassmethod(); and not this: 1- outerclass outerinstance=new outerclass(); 2- outerinstance.staticnestedclass.anestedclassmethod(); use on inner classes, keyword static indicates can access inner class without instance of outer class. for example: public class outer { public static class inner { /* code here. */ } } with construction, can create instance of inn
Read more

c# - Bluetooth LE CanUpdate Characteristic property -

-
i building xamarin.forms cross platform mobile app, uses monkey.robotics bluetoth low energy functionality. connecting mbed based implimentation of custom gatt service . in xamarin c#, triggers characteristic. canupdate property in monkey.robotics? this standard example c# based on: if (characteristic.canupdate) { characteristic.valueupdated += (s, e) => { debug.writeline("characteristic.valueupdated"); device.begininvokeonmainthread( () => { updatedisplay(characteristic); }); isbusy = false; // spin until first result received }; isbusy = true; characteristic.startupdates(); } this has been working, since changed own custom gatt service connecting to, canupdate property false. property , how triggered? me debugging gatt service code. thanks monkey.robotics open sour
Read more

JavaScript - Replace variable from string in all occurrences -

-
ok, know if have character '-' , want remove in places in string javascript, ... someword = someword.replace(/-/g, ''); but, when applying array of characters, s not working ... const badchars = ('\/:*?"<>|').split(''); let filename = title.replace(/ /g, '-').tolocalelowercase(); (let item = 0; item < badchars.length; item++) { // below not work global '/ /g' filename = filename.replace(/badchars[item]/g, ''); } any ideas? /badchars[item]/g looks badchars , literally, followed i , t , e , or m . if you're trying use character badchars[item] , you'll need use regexp constructor, , you'll need escape regex-specific characters. escaping regular expression has been well-covered . using that: filename = filename.replace(new regexp(regexp.quote(badchars[item]), 'g'), ''); but , don't want that. want character class: let filename = title.replac
Read more