enviornment of child function created by loadstring lua -

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why calls f() , g() give different results? both inherit environment parent function, run, f() not change j.

mystring = "print('i,j in mystring before setting', i, j);\             = 'fi'; j ='fj'\             print('i,j in mystring after setting', i,j)" j = 1 print('j initial value', j)  function run(i)     = 'i'     print('i initial value', i)     f = loadstring(mystring)     if not f         print('load failed')     else         print('=== load ok, execute')         f()         print('=== end of execution')     end     print('i,j after f()', i,j)      g = function()         = 'gi'; j = 'gj'     end     g()     print('i,j after g()', i,j) end  run(i)

results:

j initial value   1 initial value   === load ok, execute i,j in mystring before setting   nil   1 i,j in mystring after setting fi fj === end of execution i,j after f()   fj i,j after g()  gi gj

note different values of after f() , g() calls.

you referring 2 separate variables.

when call f() it's accessing global i, whereas accessing run's argument in g().


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